Medium
Given two integer arrays inorder and postorder where inorder is the inorder traversal of a binary tree and postorder is the postorder traversal of the same tree, construct and return the binary tree.
Example 1:

Input: inorder = [9,3,15,20,7], postorder = [9,15,7,20,3]
Output: [3,9,20,null,null,15,7]
Example 2:
Input: inorder = [-1], postorder = [-1]
Output: [-1]
Constraints:
1 <= inorder.length <= 3000postorder.length == inorder.length-3000 <= inorder[i], postorder[i] <= 3000inorder and postorder consist of unique values.postorder also appears in inorder.inorder is guaranteed to be the inorder traversal of the tree.postorder is guaranteed to be the postorder traversal of the tree./**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func buildTree(inorder []int, postorder []int) *TreeNode {
inIndex := []int{len(inorder) - 1}
postIndex := []int{len(postorder) - 1}
return helper(inorder, postorder, inIndex, postIndex, 1<<31-1)
}
func helper(in, post []int, index, pIndex []int, target int) *TreeNode {
if index[0] < 0 || in[index[0]] == target {
return nil
}
root := &TreeNode{Val: post[pIndex[0]]}
pIndex[0]--
root.Right = helper(in, post, index, pIndex, root.Val)
index[0]--
root.Left = helper(in, post, index, pIndex, target)
return root
}