Medium
Given two integers n
and k
, return all possible combinations of k
numbers out of the range [1, n]
.
You may return the answer in any order.
Example 1:
Input: n = 4, k = 2
Output: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
Example 2:
Input: n = 1, k = 1
Output: [[1]]
Constraints:
1 <= n <= 20
1 <= k <= n
from typing import List
class Solution:
def combine(self, n: int, k: int) -> List[List[int]]:
ans = []
# Boundary case
if n > 20 or k < 1 or k > n:
return ans
self._backtrack(ans, n, k, 1, [])
return ans
def _backtrack(self, ans: List[List[int]], n: int, k: int, s: int, stack: List[int]):
# Base case
# If k becomes 0
if k == 0:
ans.append(stack[:])
return
# Start with s till n-k+1
for i in range(s, n - k + 2):
stack.append(i)
# Update start for recursion and decrease k by 1
self._backtrack(ans, n, k - 1, i + 1, stack)
stack.pop()