Medium
Given an integer array nums
where every element appears three times except for one, which appears exactly once. Find the single element and return it.
You must implement a solution with a linear runtime complexity and use only constant extra space.
Example 1:
Input: nums = [2,2,3,2]
Output: 3
Example 2:
Input: nums = [0,1,0,1,0,1,99]
Output: 99
Constraints:
1 <= nums.length <= 3 * 104
-231 <= nums[i] <= 231 - 1
nums
appears exactly three times except for one element which appears once.from typing import List
class Solution:
def singleNumber(self, nums: List[int]) -> int:
ones = 0
twos = 0
for num in nums:
ones = (ones ^ num) & (~twos)
twos = (twos ^ num) & (~ones)
return ones