Easy
Given an integer array nums
and an integer k
, return true
if there are two distinct indices i
and j
in the array such that nums[i] == nums[j]
and abs(i - j) <= k
.
Example 1:
Input: nums = [1,2,3,1], k = 3
Output: true
Example 2:
Input: nums = [1,0,1,1], k = 1
Output: true
Example 3:
Input: nums = [1,2,3,1,2,3], k = 2
Output: false
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
0 <= k <= 105
from typing import List, Dict
class Solution:
def containsNearbyDuplicate(self, nums: List[int], k: int) -> bool:
map_dict = {}
length = len(nums)
for i in range(length):
index = map_dict.get(nums[i])
if index is not None and abs(index - i) <= k:
return True
map_dict[nums[i]] = i
return False